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Posted by yassar - 10-04-2017, 07:48 PM
hi wld like 2 download the application form for the next intake
Posted by jerinpunnen - 10-04-2017, 07:48 PM
My sister wants to apply and she is interested to train at your college
Posted by ajaykiranvarma - 10-04-2017, 07:48 PM
Hi am Gilton i would like to get details on download of morgan zintec application form
Posted by shockzz - 10-04-2017, 07:48 PM
Firefox is unable to download the Form. Arent there is no other means to get the form?

Trevor
Posted by jaswalsaurabh - 10-04-2017, 07:48 PM
My sister want to apply for your next intake so he asked me to download this form for her. Victor
Posted by greatsumit - 10-04-2017, 07:48 PM
(08-02-2016, 06:22 AM)Guest Wrote: Download morgan zintech application form
Posted by ANUP S - 10-04-2017, 07:48 PM
To get data about it please visit the given page link :

http://kootol.info/paper-stock/morgan-zi...form.xhtml
Posted by priyababa - 10-04-2017, 07:48 PM
My name is Privilege Makwari, i would like to get details on download morgan zintec application form for September 2016 intake. I live in Zengeza 3 Chitungwiza and i last studied Information and Technology at Ranch House College in 2012 and completed my attachment at Zimbabwe Electricity Transmission and Distribution Company
Posted by aravind - 10-04-2017, 07:48 PM
VISION

To be the centre for quality teaching practice supervision in which instructional deficiencies are taken care of through the involvement of stakeholders and the use of individualised student teacher instruction/ coaching.

MISSION

To afford every student teacher on teaching practice an opportunity for a face to face interaction with supervisors at the service delivery point.

ACTIVITIES

Planning teaching practice supervision schedules.
Creating teaching practice profiles.
Planning remedial session for low achievers as well as creating opportunities for high achievers to excel.
Planning mentoring workshops.
Presenting student teachers to the Department of Teacher Education of the University of Zimbabwe for examining.
Preparing student teachers for peer group teaching and micro-teaching.
Supervising micro- teaching.
Delivering lectures on topics to do with teaching practice.
Identifying student teachers who need counselling services while on teaching practice and referring these student teachers to counselling specialists.
Assisting student teachers to overcome challenges they meet while on teaching practice.
Working with partners such as school administrators to create an environment that is conducive to effective teaching practice .
Posted by vaisakh - 10-04-2017, 07:48 PM
Name study of De Morgan s both theorems.
Aim to study the De Morgan s theorems and their working using logic circuits.
Apparatus IC 7404, IC 7408, IC 7432, circuit board, power supply +5V DC, LED, connecting wires, soldering iron, cutter etc.
Circuit diagrams
[attachment=13792]
[attachment=13793]
Procedure
1) You are given IC 7404, IC 7408 and IC 7432. Identify the ICs by reading their numbers and details from above given pin configurations.
2) Connect the gates with their respective pin numbers to satisfy both De Morgan s theorems as shown in the circuit diagrams.
3) Connect final output of the circuit to the LED.
4) Verify the truth table for each theorem by giving different combinations of logic inputs as shown the respective truth tables.
5) Write the observed truth table of each theorem and hence, write the logic equation.
Brief theory
First theorem it states that the complement of product is equal to the sum of the complements.
Logic equation
Proof we shall prove above theorem by showing that LHS & RHS of given equation are equal.
LHS =
Let A = B = 0; then = = = 1
Let A = 0 & B = 1; then = = = 1
Let A = 1 & B = 0; then = = = 1
Let A = B = 1; then = = = 0
RHS =
Let A = B = 0; then = = 1 + 1 = 1
Let A = 0 & B = 1; then = = 1+ 0 = 1
Let A = 1 & B = 0; then = = 0 + 1 = 1
Let A = B = 1; then = = 0 + 0 = 0 Thus, LHS = RHS, hence proved.
Second theorem it states that the complement of sum is equal to the product of the complements.
Logic equation
Proof we shall prove the theorem by showing that LHS & RHS of given equation are equal.
LHS =
Let A = B = 0; then = = = 1
Let A = 0 & B = 1; then = = = 0
Let A = 1 & B = 0; then = = = 0
Let A = B = 1; then = = = 0
RHS =
Let A = B = 0; then = = 1.1 = 1
Let A = 0 & B = 1; then = = 1.0 = 0
Let A = 1 & B = 0; then = = 0.1 = 0
Let A = B = 1; then = = 0.0 = 0 Thus, LHS = RHS, hence proved.
Conclusion in this way, we have studied the De Morgan s both theorems and found that
and
[attachment=13794]
In general, and
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